3x^2/2y=-2/3

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Solution for 3x^2/2y=-2/3 equation: 


x in (-oo:+oo)

((3*x^2)/2)*y = -2/3 // + -2/3

((3*x^2)/2)*y-(-2/3) = 0

((3*x^2)/2)*y+2/3 = 0

3/2*x^2*y = -2/3 // : 3/2*y

x^2 = -4/9*y^-1

x^2 = -4/9*y^-1 // ^ 1/2

abs(x) = (-4/9)^(1/2)*y^(-1/2)

x = (-4/9)^(1/2)*y^(-1/2) or x = -((-4/9)^(1/2)*y^(-1/2))

x in { (-4/9)^(1/2)*y^(-1/2), -((-4/9)^(1/2)*y^(-1/2)) }

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